Getting size of void* for creating a simple generic dynamically allocated array - C

Question

I have created a simple dynamic array in C.

typedef struct varray_t
{
    void **memory;
    size_t allocated;
    size_t used;
    int index;              
} varray;

void
varray_init(varray **array)
{
    *array = (varray*) malloc (sizeof(varray));    
    (*array)->memory = NULL;
    (*array)->allocated = 0;
    (*array)->used = 0;
    (*array)->index = -1;
}

void
varray_push(varray *array, void *data, size_t size)
{
    if ((array->allocated - array->used) < size) {
        array->memory = realloc(array->memory, array->allocated + size);
        array->allocated = array->allocated + size;
    }

    array->used = array->used + size;   
    array->memory[++array->index] = data;
}

int
varray_length(varray *array)
{
    return array->index + 1;
}

void
varray_clear(varray *array)
{
    int i;
    for(i = 0; i < varray_length(array); i++)
    {
        array->memory[i] = NULL;
    }    
    array->used = 0;
    array->index = -1;
}

void 
varray_free(varray *array)
{
    free(array->memory);
    free(array);
}

void*
varray_get(varray *array, int index)
{
    if (index < 0 || index > array->index)
        return NULL;

    return array->memory[index];
}

This is working fine. But to add an item into the array, caller has to pass in the size of the element getting added. I can't figure out another way to get the size from the passed in void*. I am wondering is there a better way to design varray_push(varray *array, void *data, size_t size) so that size can be infered?

Any help would be great

Edited code after the suggestions

My array will contain only pointer elements. I have modified the code according to Blastfurnace's suggestion. New code will use sizeof(void*) and resize memory by a constant propotion to get amortized constant time on inserts.

void
varray_push(varray *array, void *data)
{
    size_t toallocate;
    size_t size = sizeof(void*);
    if ((array->allocated - array->used) < size) {
        toallocate = array->allocated == 0 ? size : (array->allocated * 2);
        array->memory = realloc(array->memory, toallocate);
        array->allocated = array->allocated + toallocate;
    }

    array->memory[++array->index] = data;
    array->used = array->used + size;
}

Answer 1

If the array is going to contain only one type at a time, then you can store the size of the type of the array in varray_init.

Also, my suggestion is that instead of allocating memory fresh for each element, you can allocate memory for constant size each time, i.e. first allocate memory for 16 elements and then when you find that array is full when pushing an element realloc for 16 + 16 = 32 elements. In this way, you can avoid calling malloc again and again and also it is not good idea to keep mallocing for small size data seperately.

EDIT: After considering Blastfurnace comment, I feel that you should actually be doing a memcpy of the data rather than assignment if your intention is to store the data and not the pointer to the data.