MDX has a nice feature whereby I can specify a range of members:
SELECT ([Canada],[2006]:[2011]) on Rows,
[Measures].members on Columns
FROM [Sales]
Is there a way to calculate the set of even years: {[2006], [2008], [2010]}? I am looking for a way that would work for large sets, so that listing the years manually is not an option.
You can filter you function using a filter function, a declared function and MOD function (MOD returns the remainder from the division - like % in Java ) :
WITH
FUNCTION isEven(Value _number) as Mod( Int(_number) , 2 ) = 0
SELECT
FILTER( [Date].[Date].[Year] as t, isEven( Year( t.current.key) ) ) on 0
FROM [Cube]
If you are using this filter often you could create a FilterEven declared function once in the script (same for isEven() )
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