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I'm trying to get an element's CSS (top and left) with jQuery:
$(element).css('top');
but instead of "12%" like it should be, I get the pixels.
How do I get the percent?
HTML:
<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-1.4.1.min.js"></script>
<style type="text/css">
.parWrapper {
position:absolute;
top: 40%
}
</style>
</head>
<body>
<div>
<div id="crap" class="parWrapper" style="left:50%">
Wrap1
</div>
<div class="parWrapper">
Wrap2
</div>
<div class="parWrapper">
Wrap3
</div>
<div class="parWrapper">
Wrap4
</div>
<div class="parWrapper">
Wrap5
</div>
</div>
</body>
774
The . position() method allows us to retrieve the current position of an element (specifically its margin box) relative to the offset parent (specifically its padding box, which excludes margins and borders). Contrast this with . offset() , which retrieves the current position relative to the document.
jQuery position() Method The position() method returns the position (relative to its parent element) of the first matched element. This method returns an object with 2 properties; the top and left positions in pixels.
jQuery offset() Method The offset() method set or returns the offset coordinates for the selected elements, relative to the document. When used to return the offset: This method returns the offset coordinates of the FIRST matched element. It returns an object with 2 properties; the top and left positions in pixels.
Difference between offset() and position() Method: The jQuery UI offset() is relative to the document. The jQuery UI position() is relative to the parent element. When you want to position a new element on top of another one which is already existing, its better to use the jQuery offset() method.
I just encountered this myself and thought it weird, too.
Instead of:
$(element).css('top');
I just did:
element.style.top
No jQuery and gives you the actual value in the type you made it (percent, ems, etc.)
103
You can do this:
$(element).position().top / $(element).parent().height() * 100
Regarding your precedent comment, if you want to work with css('top'), don't forget to parseInt it.
39
This is also an option:
$(element)[0].style.top
There is a (very easy) way to do this!
Even when using stylesheets.
The key is to prevent jquery from calculating the value by temporarily hiding the parent.
$(element).parent().hide();
var top = $(element).css("top");
$(element).parent().show();
console.log(top);
voila!
If you want just the number without the "%" use
top = parseFloat(top);
BTW: Don't worry, the hiding and reshowing is so quick, it won't be visible for your users.
35
calculate it by your own:
($(element).css('top') / parentHeight) * 100;
I had a need to calculate something similiar but in my case it was the left %, you can update the code below to use the window height if you are going for a vertical percentage value -
getLeftPercent = function() {
var leftStr = $('#my-obj').css('left'),
pxPos = leftStr.indexOf('px'),
leftVal = leftStr.substr(0, pxPos),
leftPercent = (leftVal / $(window).width() * 100).toString(),
dotPos = leftPercent.indexOf('.'),
leftPercentStr = dotPos == -1 ? leftPercent + '%' : leftPercent.substr(0, dotPos) + '%';
return leftPercentStr;
};
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