Getting attribute's value using BeautifulSoup

Question

I'm writing a python script which will extract the script locations after parsing from a webpage. Lets say there are two scenarios :

<script type="text/javascript" src="http://example.com/something.js"></script>

and

<script>some JS</script>

I'm able to get the JS from the second scenario, that is when the JS is written within the tags.

But is there any way, I could get the value of src from the first scenario (i.e extracting all the values of src tags within script such as http://example.com/something.js)

Here's my code

#!/usr/bin/python

import requests 
from bs4 import BeautifulSoup

r  = requests.get("http://rediff.com/")
data = r.text
soup = BeautifulSoup(data)
for n in soup.find_all('script'):
    print n 

Output : Some JS

Output Needed : http://example.com/something.js

Answer 1

It will get all the src values only if they are present. Or else it would skip that <script> tag

from bs4 import BeautifulSoup
import urllib2
url="http://rediff.com/"
page=urllib2.urlopen(url)
soup = BeautifulSoup(page.read())
sources=soup.findAll('script',{"src":True})
for source in sources:
 print source['src']

I am getting following two src values as result

http://imworld.rediff.com/worldrediff/js_2_5/ws-global_hm_1.js
http://im.rediff.com/uim/common/realmedia_banner_1_5.js

I guess this is what you want. Hope this is useful.

Answer 2

Get 'src' from script node.

import requests 
from bs4 import BeautifulSoup

r  = requests.get("http://rediff.com/")
data = r.text
soup = BeautifulSoup(data)
for n in soup.find_all('script'):
    print "src:", n.get('src') <====