Getting All Elements In An Array (Javascript)

Question

I am trying to check if a string contains certain words which I had stored in an array... however I'm new to JS, so I don't exactly know how to check all of the elements inside the Array.

Here is an Example:

const fruits = ["apple", "banana", "orange"]

I am actually checking if someone sends swearwords in a chat.

if(message.content.includes(fruits)){executed code}

However my issue is when I check for fruits it does anything but when I check for a specific element in the array like fruits[0] //returns apple it will actually check for that... So my issue / question is how do I check the string for all of the elements in the array not just apples.

Answer 1

Your usage of includes is wrong.

From MDN:

The includes() method determines whether an array includes a certain value among its entries, returning true or false as appropriate.

arr.includes(valueToFind[, fromIndex])

const fruits = ["apple", "banana", "orange"];
const swearWord = "orange";

// execute is available
if (fruits.includes(swearWord))
  console.log("Swear word exists.");
else 
  console.log("Swear word doesn't exist.");

To check the otherway, if string contains the array's swearword:

const fruits = ["apple", "banana", "orange"];
const swearWord = "this contains a swear word. orange is the swear word";

// execute is available
if (checkForSwearWord())
  console.log("Swear word exists.");
else
  console.log("Swear word doesn't exist.");

function checkForSwearWord() {
  for (const fruit of fruits) 
    if (swearWord.includes(fruit)) return true;
  return false;
}