Getting a queue without providing its all properties

Question

I am trying to write a consumer for an existing queue.

RabbbitMQ is running in a separate instance and queue named "org-queue" is already created and binded to an exchange. org-queue is a durable queue and it has some additional properties as well.

Now I need to receive messages from this queue. I have use the below code to get instance of the queue

conn = Bunny.new
conn.start
ch = conn.create_channel    
q = ch.queue("org-queue")

It throws me an error stating different durable property. It seems by default the Bunny uses durable = false. So I've added durable true as parameter. Now it states the difference between other parameters. Do I need to specify all the parameters, to connect to it? As rabbitMQ is maintained by different environment, it is hard for me to get all the properties.

Is there a way to get list of queues and listening to the required queue in client instead of connecting to a queue by all parameters.

Answer 1

Have you tried the :passive=true parameter on queue()? A real example is the rabbitmq plugin of logstash. :passive means to only check queue existence rather than to declare it when consuming messages from it.

Answer 2

Based on the documentation here http://reference.rubybunny.info/Bunny/Queue.html and http://reference.rubybunny.info/Bunny/Channel.html

Using the ch.queues() method you could get a hash of all the queues on that channel. Then once you find the instance of the queue you are wanting to connect to you could use the q.options() method to find out what options are on that rabbitmq queue.

Seems like a round about way to do it but might work. I haven't tested this as I don't have a rabbitmq server up at the moment.