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I know it's very easy to do in Python: someList[1:2]
But how do you this in Lua? That code gives me a syntax error.
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For Lua, that means "index the table io using the string "read" as the key". When a program has no references to a table left, Lua memory management will eventually delete the table and reuse its memory. Notice the last line: Like global variables, table fields evaluate to nil if they are not initialized.
To access the value associated with the key in a table you can use the table[key] syntax: > t = {} > t["foo"] = 123 -- assign the value 123 to the key "foo" in the table > t[3] = "bar" -- assign the value "bar" to the key 3 in the table > = t["foo"] 123 > = t[3] bar.
In Lua, if you want to call a variable function f with variable arguments in an array a , you simply write f(unpack(a)) The call to unpack returns all values in a , which become the arguments to f . For instance, if we execute f = string.find a = {"hello", "ll"}
If you want to delete items from an array (a table with numeric indices), use ArrayRemove() . By the way, the tests above were all executed using Lua 5.3. 4 , since that's the standard runtime most people use.
{unpack(someList, from_index, to_index)}
But table indexes will be started from 1, not from from_index
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The unpack function built into Lua can do this job for you:
Returns the elements from the given table.
You can also use
x, y = someList[1], someList[2]
for the same results. But this method can not be applied to varying length of lua-table.
table.unpack (list [, i [, j]])
Returns the elements from the given table. This function is equivalent to
return list[i], list[i+1], ···, list[j]
By default, i is 1 and j is #list.
A codepad link to show the working of the same.
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