getopt always returns 1

Question

I want to use getopt to get the argument list of my console tool. When I call my tool like below getopt returns always 1 and doesn't mactch any switch/case.

Am I doing something wrong?

  mytool -f farg -d darg

  int 
  main(int argc, char** argv) {
  int c;
  while((c = getopt(argc, argv, "f:d:h") != -1)) {

      switch(c) {
        case'f':
        break;

        default:
        break;
      }
  }

Answer 1

while((c = getopt(argc, argv, "f:d:h") != -1))

It works like

c = (getopt(argc, argv, "f:d:h") != -1)

Well, that is 1 always because the result of the comparison is stored to c. In your case the getopt does not return -1. If it returns -1 then c would be 0. The fix is

while((c = getopt(argc, argv, "f:d:h")) != -1)