*"Hätten Hüte ein ä im Namen, wären sie möglicherweise keine Hüte mehr, sondern Häte."
72 -61 -92 116 116 101 ...*
GetBytes() returns negative number (-61, () ) at the char 'ä'.
How to get the normal ascii value?
Here, string is an object of the String class. The getBytes() method returns a byte array.
Negative numbers are stored by decrementing from zero, thus -1 value is always 2(N)-1. The lowest negative number that can be represented is -2(N-1). For the byte case we have 8 bits, even though unsigned values for a byte range from zero up to 255, in Java it's regarded as signed, thus they range from -128 up to 127.
getbytes() function in java is used to convert a string into a sequence of bytes and returns an array of bytes.
In Java, byte is an 8-bit signed (positive and negative) data type, values from -128 (-2^7) to 127 (2^7-1) . For unsigned byte , the allowed values are from 0 to 255 .
GetBytes() returns negative number (-61, () ) at the char 'ä'.
Well getBytes()
is going to use the platform default encoding, unless you specify an encoding, which you should. I would recommend UTF-8 normally. For example, in Java 7:
byte[] data = text.getBytes(StandardCharsets.UTF_8);
byte
in Java is unfortunately signed - but you can think of it as being just 8 bits. If you want to see the effective unsigned, just use:
int unsigned = someByte & 0xff;
How to get the normal ascii value?
That character doesn't exist in ASCII. All ASCII characters are in the range U+0000 to U+007F.
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