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I have a date in this format 2068-06-15. I want to get the year from the date, using php functions. Could someone please suggest how this could be done.
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$date = DateTime::createFromFormat("Y-m-d", "2068-06-15"); echo $date->format("Y");
@scoota269 is right - and you can test this using echo date("Y-m-d", $oldDateUnix) . In this case, it even bugs up and results (1970-01-01) which is unix time 0.
You can use the date function. I'm using strtotime to get the timestamp to that day ; there are other solutions, like mktime , for instance.
The strtotime() function parses an English textual datetime into a Unix timestamp (the number of seconds since January 1 1970 00:00:00 GMT). Note: If the year is specified in a two-digit format, values between 0-69 are mapped to 2000-2069 and values between 70-100 are mapped to 1970-2000.
$date = DateTime::createFromFormat("Y-m-d", "2068-06-15"); echo $date->format("Y"); The DateTime class does not use an unix timestamp internally, so it han handle dates before 1970 or after 2038.
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