Get the Sum of a column grouped by another column then grouped into another

Question

I've been trying for a while now to figure this out but my lack of more advanced SQL skills are holding me back.

Executions(TradeDate, Symbol, Side, Price, Under, Account)

TEMP DATA:
2012-06-20, AAPL 120716C00600000, BUY, 3.25, AAPL, XYZ123
2012-06-20, AAPL 120716C00600000, SELL, 3.30, AAPL, XYZ123
2012-06-20, AAPL 120716C00600000, BUY, 3.25, AAPL, XYZ123
2012-06-20, AAPL 120716C00600000, SELL, 3.30, AAPL, XYZ123
2012-06-20, GRPN 120716C00027000, BUY, 2.25, GRPN, XYZ123
2012-06-20, GRPN 120716C00027000, SELL, 2.30, GRPN, XYZ123
2012-06-20, GRPN 120716C00027000, SELL, 2.30, GRPN, XYZ123
2012-06-20, GRPN 120716C00027000, BUY, 2.25, GRPN, XYZ123


-UNDER----Side(Buy)----Side(Sell)
 AAPL      6.50         6.60
 GRPN      4.50         4.60

As you can see I'm trying to get the SUM of the Price for each Side and then grouped by the Under.

Answer 1

Use GROUP BY to group by Under column and CASE associated with SUM to get the needed results:

SELECT e.Under,
       SUM(case when e.Side = 'BUY' them e.Price else 0 end) as 'Side(Buy)',
       SUM(case when e.Side = 'SELL' them e.Price else 0 end) as 'Side(Sell)'
FROM Executions e
GROUP BY e.Under