Get the number of digits in an int

Question

How do I detect the length of an integer? In case I had le: int test(234567545);

How do I know how long the int is? Like telling me there is 9 numbers inside it???

*I have tried:**

char buffer_length[100];


    //  assign directly to a string.

    sprintf(buffer_length, "%d\n", 234567545);

    string sf = buffer_length;


    cout <<sf.length()-1 << endl;

But there must be a simpler way of doing it or more clean...

Answer 1

How about division:

int length = 1;
int x = 234567545;
while ( x /= 10 )
   length++;

or use the log10 method from <math.h>.

Note that log10 returns a double, so you'll have to adjust the result.