get the last sunday and saturday's date in python

Question

Looking to leverage datetime to get the date of beginning and end of the previous week, sunday to saturday.

So, if it's 8/12/13 today, I want to define a function that prints:

Last Sunday was 8/4/2013 and last Saturday was 8/10/2013

How do I go about writing this?

EDIT: okay, so there seems to be some question about edge cases. For saturdays, I want the same week, for anything else, I'd like the calendar week immediately preceding today's date.

Answer 1

datetime.date.weekday returns 0 for Monday. You need to adjust that.

Try following:

>>> import datetime >>> today = datetime.date.today() >>> today datetime.date(2013, 8, 13) >>> idx = (today.weekday() + 1) % 7 # MON = 0, SUN = 6 -> SUN = 0 .. SAT = 6 >>> idx 2 >>> sun = today - datetime.timedelta(7+idx) >>> sat = today - datetime.timedelta(7+idx-6) >>> 'Last Sunday was {:%m/%d/%Y} and last Saturday was {:%m/%d/%Y}'.format(sun, sat) 'Last Sunday was 08/04/2013 and last Saturday was 08/10/2013' 

If you are allowed to use python-dateutil:

>>> import datetime >>> from dateutil import relativedelta >>> today = datetime.datetime.now() >>> start = today - datetime.timedelta((today.weekday() + 1) % 7) >>> sat = start + relativedelta.relativedelta(weekday=relativedelta.SA(-1)) >>> sun = sat + relativedelta.relativedelta(weekday=relativedelta.SU(-1)) >>> 'Last Sunday was {:%m/%d/%Y} and last Saturday was {:%m/%d/%Y}'.format(sun, sat) 'Last Sunday was 08/04/2013 and last Saturday was 08/10/2013' 

Answer 2

I found the best answer from here working fine in my case

try this

from datetime import datetime,timedelta import time  def last_day(d, day_name):     days_of_week = ['sunday','monday','tuesday','wednesday',                         'thursday','friday','saturday']     target_day = days_of_week.index(day_name.lower())     delta_day = target_day - d.isoweekday()     if delta_day >= 0: delta_day -= 7 # go back 7 days     return d + timedelta(days=delta_day)