Get the id + the map of a vertex on Gremlin?

Question

g.v(1).id

gives me vertex 1 id,

g.v(1).map

gives me vertex 1 properties.

But, how can I get a hash with id and propeties at the same time

Answer 1

I know that it's an old question - so answers below will work on older versions of TinkerPop (3<); just if anyone (like me) stumbles upon this question and looks for a solution that works on TinkerPop 3 - the same result can be achieved by calling valueMap with 'true' argument, like this:

gremlin> g.v(1).valueMap(true)

reference may be found in docs here

Answer 2

As of Gremlin 2.4.0 you can also do something like:

gremlin> g = TinkerGraphFactory.createTinkerGraph()
==>tinkergraph[vertices:6 edges:6]
gremlin> g.v(1).out.map('name','age','id') 
==>{id=2, age=27, name=vadas}
==>{id=4, age=32, name=josh}
==>{id=3, age=null, name=lop}

Another alternative using transform():

gremlin> g.v(1).out.transform{[it.id,it.map()]}
==>[2, {age=27, name=vadas}]
==>[4, {age=32, name=josh}]
==>[3, {name=lop, lang=java}]

Answer 3

if implementing with Java use

g.V(1).valueMap().with(WithOptions.tokens).toList()