Get size of pointer in C

Question

How do I get the size of a pointer in C using sizeof? I want to malloc some memory to store a pointer (not the value being pointed to).

Answer 1

Given an arbitrary type (I've chosen char here, but that is for sake of concrete example):

char *p;

You can use either of these expressions:

sizeof(p)
sizeof(char *)

Leading to a malloc() call such as:

char **ppc = malloc(sizeof(char *));
char **ppc = malloc(sizeof(p));
char **ppc = malloc(sizeof(*ppc));

The last version has some benefits in that if the type of ppc changes, the expression still allocates the correct space.

Answer 2

This should do the trick:

sizeof(void*)

Answer 3

char *ptr;
char **ptr2 = malloc(sizeof(ptr));

should be able to achieve your purpose. No matter what the platform is, this code should work.