I have a s3 bucket named 'Sample_Bucket' in which there is a folder called 'Sample_Folder'. I need to get only the names of all the files in the folder 'Sample_Folder'.
I am using the following code to do so -
import boto3
s3 = boto3.resource('s3', region_name='us-east-1', verify=False)
bucket = s3.Bucket('Sample_Bucket')
for files in bucket.objects.filter(Prefix='Sample_Folder):
print(files)
The variable files contain object variables which has the filename as key.
s3.ObjectSummary(bucket_name='Sample-Bucket', key='Sample_Folder/Sample_File.txt')
But I need only the filename. How do I extract that? Or is there any other way to do it?
Sign in to the AWS Management Console and open the Amazon S3 console at https://console.aws.amazon.com/s3/ . In the Buckets list, choose the name of the bucket that contains the object. In the Objects list, choose the name of the object for which you want an overview. The object overview opens.
Use the cp command to download a folder inside a bucket from S3 to local. recursive option will download all files and folders if you have a recursive folder/file structure.
Reading objects without downloading them Similarly, if you want to upload and read small pieces of textual data such as quotes, tweets, or news articles, you can do that using the S3 resource method put(), as demonstrated in the example below (Gist).
Here you go.
import boto3
bucket = "Sample_Bucket"
folder = "Sample_Folder"
s3 = boto3.resource("s3")
s3_bucket = s3.Bucket(bucket)
files_in_s3 = [f.key.split(folder + "/")[1] for f in s3_bucket.objects.filter(Prefix=folder).all()]
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