Get namespace from class

Question

Is it possible within TypeScript to get the namespace of a class?

namespace My.API.DTO {
    export class Something {

        // ID
        public id: number;

        public constructor() { }
    }
}

I can write the following to get class name

console.log(My.API.DTO.Something.name);

Outputs

Something

I want the output to be

My.API.DTO.Something

I'm open to using a third party library to help with this. Please note I generate all my TypeScript DTO classes from their C# counterparts using the TypeWriter Visual Studio plugin.

Answer 1

If you have access to the root namespace -- My in your case -- you can recursively patch all classes (all functions actually) with a helper method:

const patch = (ns: object, path?: string) => {
    Object.keys(ns).forEach((key) => {
        const value = ns[key];
        const currentPath = path ? `${path}.${key}` : key;
        if (typeof value === 'object') {
            patch(value, currentPath);
        }
        if (typeof value === 'function') {
            Object.defineProperty(value, 'name', {
                value: currentPath,
                configurable: true,
            });
        }
    })
}

namespace My.API.DTO {
    export class Something {

        // ID
        public id: number;

        public constructor() { }
    }
}

patch({ My });

console.log(My.API.DTO.Something.name); // My.API.DTO.Something

You just have to be aware that this patches any function inside the tree since ES6 classes are nothing more. The drawback is that you'll have to patch each namespace root individually since patch(window) will most likely result in a too much recursion error and probably other unwanted side-effects.

Note that instead of using object destructuring you could also call patch like this:

patch(My, 'My');

Demo