What is the way of printing "Foo" here? In this example, what prints is "string".
http://play.golang.org/p/ZnK6PRwEPp
type A struct {
Foo string
}
func (a *A) PrintFoo() {
fmt.Println("Foo value is " + a.Foo)
}
func main() {
a := &A{Foo: "afoo"}
val := reflect.Indirect(reflect.ValueOf(a))
fmt.Println(val.Field(0).Type().Name())
}
You want val.Type().Field(0).Name
. The Field
method on reflect.Type
will return a struct describing that field, which includes the name, among other information.
There is no way to retrieve the field name for a reflect.Value
representing a particular field value, since that is a property of the containing struct.
You need to Get the Field of the Type Definition not of the Value.
http://play.golang.org/p/7Bc7MJikbJ
package main
import "fmt"
import "reflect"
type A struct {
Foo string
}
func (a *A) PrintFoo() {
fmt.Println("Foo value is " + a.Foo)
}
func main() {
a := &A{Foo: "afoo"}
val := reflect.Indirect(reflect.ValueOf(a))
fmt.Println(val.Type().Field(0).Name)
}
I think the better way to get the fields' name in the struct is
func main() {
a := &A{Foo: "afoo"}
val := reflect.ValueOf(a).Elem()
for i:=0; i<val.NumField();i++{
fmt.Println(val.Type().Field(i).Name)
}
}
There are two tips:
.Elem()
after you reflect.ValueOf(a)
, because in your case, a is a pointer.val.Field(i).Type().Name
is totally different from val.Type().Field(i).Name
. The latter one can get the name of the field in the structHope that it is helpful..
If you want to have a look at more cases, please check my 2mins article
With the new Names
method of the structs package it's even more easier:
package main
import (
"fmt"
"github.com/fatih/structs"
)
type A struct {
Foo string
Bar int
}
func main() {
names := structs.Names(&A{})
fmt.Println(names) // ["Foo", "Bar"]
}
You can also use https://github.com/fatih/structs
// Convert the fields of a struct to a []*Field
fields := s.Fields()
for _, f := range fields {
fmt.Printf("field name: %+v\n", f.Name())
}
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