I have the array of dates in Y-m-d H:i:s
format like:
array(5) { [0]=> string(19) "2012-06-11 08:30:49" [1]=> string(19) "2012-06-07 08:03:54" [2]=> string(19) "2012-05-26 23:04:04" [3]=> string(19) "2012-05-27 08:30:00" [4]=> string(19) "2012-06-08 08:30:55" }
I would like to know the most recent date.
In other words, today is June 13th 2012, which datetime is closest to today's date?
From my sample array, I am expecting 2012-06-11 08:30:49
.
How can I do that?
push(new Date('2017/10/20')); let maxDate = dateArray[0]; for (let date of dateArray) { if (date > maxDate) { maxDate = date; } } console. log(`Max date = ${maxDate}`); Here, dateArray is an array of Date objects. maxDate is used to hold the largest Date object.
To sort an array of objects by date in TypeScript: Call the sort() method on the array, passing it a function. The function will be called with 2 objects from the array. Subtract the timestamp of the date in the second object from the timestamp of the date in the first.
Use max()
, array_map()
, and strtotime()
.
$max = max(array_map('strtotime', $arr)); echo date('Y-m-j H:i:s', $max); // 2012-06-11 08:30:49
Do a loop, convert the values to date, and store the most recent, in a var.
$mostRecent= 0; foreach($dates as $date){ $curDate = strtotime($date); if ($curDate > $mostRecent) { $mostRecent = $curDate; } }
something like that... you get the idea If you want most recent BEFORE today :
$mostRecent= 0; $now = time(); foreach($dates as $date){ $curDate = strtotime($date); if ($curDate > $mostRecent && $curDate < $now) { $mostRecent = $curDate; } }
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