Get JSON result with GET request and parameters with Alamofire

Question

This is my url String with paramaters. http://api.room2shop.com/api/product/GetProducts?categoryId=22&filter=2&pageNumber=1 through which I am getting my JSON data. I have AFWrapper.swift file in which I have defined function for GETrequest.

import UIKit
import Alamofire
import SwiftyJSON

class AFWrapper: NSObject {

    class func requestGETURL(strURL: String, params : [String : AnyObject]?, success:(JSON) -> Void, failure:(NSError) -> Void) {
        Alamofire.request(.GET, strURL, parameters: params, encoding: ParameterEncoding.JSON).responseJSON { (responseObject) -> Void in

            print(responseObject)

            if responseObject.result.isSuccess {
                let resJson = JSON(responseObject.result.value!)
                success(resJson)
            }
            if responseObject.result.isFailure {
                let error : NSError = responseObject.result.error!
                failure(error)
            }


           }
        }
}

Now I am calling this function in my ViewController.swift file.

let strURL = "http://api.room2shop.com/api/product/GetProducts"
    let param = ["categoryId": "22", "filter": "2", "pageNumber": "1"]
    AFWrapper.requestGETURL(strURL, params: param, success: {
        (JSONResponse) -> Void in

        if let resData = JSONResponse["ProductList"].arrayObject {
            for item in resData {
                self.TableData.append(datastruct(add: item as! NSDictionary))
            }

        do
        {
            try self.read()
        }
        catch
        {
        }
        self.do_table_refresh()
    }

}) {
    (error) -> Void in
    print(error)
}

but it is not giving me any response and giving me this error.

FAILURE: Error Domain=NSURLErrorDomain Code=-1017 "cannot parse response" UserInfo={NSErrorFailingURLStringKey=http://api.room2shop.com/api/product/GetProducts, _kCFStreamErrorCodeKey=-1, NSErrorFailingURLKey=http://api.room2shop.com/api/product/GetProducts, NSLocalizedDescription=cannot parse response, _kCFStreamErrorDomainKey=4, NSUnderlyingError=0x78ecf180 {Error Domain=kCFErrorDomainCFNetwork Code=-1017 "(null)" UserInfo={_kCFStreamErrorDomainKey=4, _kCFStreamErrorCodeKey=-1}}} Error Domain=NSURLErrorDomain Code=-1017 "cannot parse response" UserInfo={NSErrorFailingURLStringKey=http://api.room2shop.com/api/product/GetProducts, _kCFStreamErrorCodeKey=-1, NSErrorFailingURLKey=http://api.room2shop.com/api/product/GetProducts, NSLocalizedDescription=cannot parse response, _kCFStreamErrorDomainKey=4, NSUnderlyingError=0x78ecf180 {Error Domain=kCFErrorDomainCFNetwork Code=-1017 "(null)" UserInfo={_kCFStreamErrorDomainKey=4, _kCFStreamErrorCodeKey=-1}}}

Can anyone tell me what am I doing wrong? I have seached this link but not getting what is wrong. URL Encode Alamofire GET params with SwiftyJSON

Answer 1

i think you should remove the parameter of "encoding: ParameterEncoding.JSON",like this:

Alamofire.request(.GET, strURL, parameters: params).responseJSON { (responseObject) -> Void in

        print(responseObject)

        if responseObject.result.isSuccess {
            let resJson = JSON(responseObject.result.value!)
            success(resJson)
        }
        if responseObject.result.isFailure {
            let error : NSError = responseObject.result.error!
            failure(error)
        }


}

Answer 2

Use this code. It is retrieving response correctly parsed in JSON.

Using Alamofire v3.0+

Alamofire.request(.GET, "http://api.room2shop.com/api/product/GetProducts?categoryId=22&filter=2&pageNumber=1")
        .responseJSON { response in
            debugPrint(response)

            switch response.result {
            case .Success(let JSON):
                print(JSON)
            case .Failure(let error):
                print(error)
            }
    }

EDIT: For accepting Parameters with GET Type Service:

Alamofire.request(.GET, "https://httpbin.org/get", parameters: ["foo": "bar"])
     .responseData { response in
         print(response.request)
         print(response.response)
         print(response.result)
      }

In this case try to not manipulate your URL String and send all parameters in terms of Dictionary like this.