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Get function by name dynamically in Kotlin

How can I dynamically get a function by name in Kotlin ?

i.e:

fun myFunc11() { println("Very useful function 11") }

val funcName = "myFunc" + 11
val funcRef = getFunction(funcName)

funcRef()

Edit: The accepted answer appears to be correct, however the code is currently hitting some bug in Kotlin. Bug report submitted: https://youtrack.jetbrains.com/issue/KT-10690

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Amir Abiri Avatar asked Jan 16 '16 06:01

Amir Abiri


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1 Answers

The global functions such as fun myFunc11() { ... } defined in file named i.e. Global.kt are compiled to static methods on a class named GlobalKt as described in the documentation.

To get a function reference by name you'll need to load the class that defines it. If you know the file name that defines the function reference you're trying to find you can do:

fun getFunctionFromFile(fileName: String, funcName: String): KFunction<*>? {
    val selfRef = ::getFunctionFromFile
    val currentClass = selfRef.javaMethod!!.declaringClass
    val classDefiningFunctions = currentClass.classLoader.loadClass("${fileName}Kt")
    val javaMethod  = classDefiningFunctions.methods.find { it.name == funcName && Modifier.isStatic(it.modifiers)}
    return javaMethod?.kotlinFunction
}

Then you can find and call function defined in Global.kt file:

fun myFunc11() { println("Very useful function 11") }

like so:

val kFunction = getFunctionFromFile("Global", "myFunc11")
kFunction?.call()

However the above is pretty useless. A better solution would be to search through all classes available in classpath and suffixed with Kt to reach all global functions. However due to nature of jvm class loaders this is a bit more involved as described in this answer.

like image 107
miensol Avatar answered Sep 22 '22 07:09

miensol