I need to get the filename from the URL address.
Here is the criteria:
It need to return empty string ""
in following scenarios:
http://somedomain.com
http://www.somedomain.com
http://somedomain.com/
http://www.somedomain.com/
And return filename.php in the following scenarios:
http://somedomain.com/filename.php?query
http://www.somedomain.com/filename.php?query
http://somedomain.com/filename.php#query
http://www.somedomain.com/filename.php#query
I found this regular expression
[\w_.-]*?(?=[\?\#])|[\w_.-]*$
from here
however it returns somedomain.com
on input http://somedomain.com
. I can't figure out how to modify it to ignore the domain when there is no /
at the end of it.
If it is difficult to do with regular expressions, I will appreciate a JavaScript solution as well.
Thanx in advance.
Assuming you are writing script in a browser, there is already a full-featured URL parser for you to take advantage of, without having to write unreliable incomplete regexen. Use an HTMLAnchorElement to read the location
-like properties host
, pathname
, search
, hash
etc.:
var a= document.createElement('a');
a.href= 'http://somedomain.com/dirname/filename.php?query';
var filename= a.pathname.split('/').pop(); // filename.php
This will put the filename in $1
: [^:]+://[^/]+/?([^?#]*)
(p.s. http://rentzsch.github.com/JSRegexTeststand/ is your friend for this sort of test)
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