Get domain name from full URL

Question

say someone enters a URL like this:

http://i.imgur.com/a/b/c?query=value&query2=value 

And I want to return: imgur.com

not i.imgur.com

This is code I have right now

$sourceUrl = parse_url($url); $sourceUrl = $sourceUrl['host']; 

But this returns i.imgur.com

Answer 1

Check the code below, it should do the job fine.

<?php  function get_domain($url) {   $pieces = parse_url($url);   $domain = isset($pieces['host']) ? $pieces['host'] : $pieces['path'];   if (preg_match('/(?P<domain>[a-z0-9][a-z0-9\-]{1,63}\.[a-z\.]{2,6})$/i', $domain, $regs)) {     return $regs['domain'];   }   return false; }  print get_domain("http://mail.somedomain.co.uk"); // outputs 'somedomain.co.uk'  ?> 

Answer 2

You need package that using Public Suffix List. Yes, you can use string functions arround parse_url() or regex, but they will produce incorrect result in complex URLs.

I recomend TLDExtract for domain parsing, here is sample code:

$url = 'http://i.imgur.com/a/b/c?query=value&query2=value';  parse_url($url, PHP_URL_HOST); // will return 'i.imgur.com'  $extract = new LayerShifter\TLDExtract\Extract(); $result = $extract->parse($url); $result->getFullHost(); // will return 'i.imgur.com' $result->getSubdomain(); // will return 'i' $result->getRegistrableDomain(); // will return 'imgur.com' $result->getSuffix(); // will return 'com'