I would like to get a different column out of each row from a matrix. For example:
A = [1,2;1,4;5,2]
B = [2;2;1]
the output should yield:
out = [2;4;5]
So in short: A
is the matrix and B
has the indices for the colums per row. How can I do this without using a loop (if it's possible)?
You can use sub2ind to convert (i,j) indices to linear indices in matrix A
idx = sub2ind(size(A), 1:size(A, 1), B');
A(idx)
ans =
2 4 5
That works assuming that vector B has as many entries as there are rows in A. In the above sub2ind generates a linear index for every pair of subsequent row numbers (1:size(A, 1)) and column numbers given in B.
You can do it by diag(A(:,B))
, there is however a loop, but only implicit. I don't know how to do it without any loop.
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