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In PostgreSQL you can use the extract() function to get the day from a date. You can also use date_part() to do the same thing. When extracting the day from a date, you need to specify what sense of the word “day” you mean. For example, “day of week”, “day of month”, “day of year”, etc.
MySQL DAYOFWEEK() Function The DAYOFWEEK() function returns the weekday index for a given date (a number from 1 to 7). Note: 1=Sunday, 2=Monday, 3=Tuesday, 4=Wednesday, 5=Thursday, 6=Friday, 7=Saturday.
Some functions of datediff use the system current date as per query syntax. select datediff function() date1, interval date2; Explanation: In the above syntax we use select clause where datediff function means various date related functions, where date1 first specified date and date2 is second specified date.
Use the PostgreSQL DATE_PART() function to retrieve the number of the day of a year from a date/time/datetime/timestamp column. This function takes two arguments. The first argument is the date part (or time part) you want the function to return. In this example, we're using ' doy ', which returns the day of the year.
Had been trying to figure out a select query to display days of week such as Monday, Tuesday, Wednesday, etc. I ended up with a select query displaying dates of a week,
select ((date_trunc('week',current_date)::date) + (i+6)) as week_date from generate_Series(0,6) i; Is there a way to get the result as Monday, Tuesday and so on.
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