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Get contents of a link tag with JavaScript - not CSS

Tags:

javascript

dom

Assuming I have

<LINK rel="Index" href="index.html">
<LINK rel="Next"  href="Chapter3.html">
<LINK rel="Prev"  href="Chapter1.html">

(taken from the W3C web site sample)

Are these accessible through the JavaScript DOM?

I want to know if I have link tags like this in the HTML document, whether they are read like the main document and added to the DOM and if I can access their DOMs as well.

like image 984
sproketboy Avatar asked Jul 29 '12 10:07

sproketboy


2 Answers

I have this code:

<script type="text/javascript">
var your_url = 'http://www.example.com';
</script>

<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.10.1/jquery.min.js" ></script>
<script type="text/javascript">
// jquery.xdomainajax.js  ------ from padolsey

jQuery.ajax = (function(_ajax){

    var protocol = location.protocol,
        hostname = location.hostname,
        exRegex = RegExp(protocol + '//' + hostname),
        YQL = 'http' + (/^https/.test(protocol)?'s':'') + '://query.yahooapis.com/v1/public/yql?callback=?',
        query = 'select * from html where url="{URL}" and xpath="*"';

    function isExternal(url) {
        return !exRegex.test(url) && /:\/\//.test(url);
    }

    return function(o) {

        var url = o.url;

        if ( /get/i.test(o.type) && !/json/i.test(o.dataType) && isExternal(url) ) {

            // Manipulate options so that JSONP-x request is made to YQL

            o.url = YQL;
            o.dataType = 'json';

            o.data = {
                q: query.replace(
                    '{URL}',
                    url + (o.data ?
                        (/\?/.test(url) ? '&' : '?') + jQuery.param(o.data)
                    : '')
                ),
                format: 'xml'
            };

            // Since it's a JSONP request
            // complete === success
            if (!o.success && o.complete) {
                o.success = o.complete;
                delete o.complete;
            }

            o.success = (function(_success){
                return function(data) {

                    if (_success) {
                        // Fake XHR callback.
                        _success.call(this, {
                            responseText: data.results[0]
                                // YQL screws with <script>s
                                // Get rid of them
                                .replace(/<script[^>]+?\/>|<script(.|\s)*?\/script>/gi, '')
                        }, 'success');
                    }

                };
            })(o.success);

        }

        return _ajax.apply(this, arguments);

    };

})(jQuery.ajax);



$.ajax({
    url: your_url,
    type: 'GET',
    success: function(res) {
        var text = res.responseText;
        // then you can manipulate your text as you wish
        alert(text);
    }
});

</script>
like image 73
otaxige_aol Avatar answered Sep 29 '22 10:09

otaxige_aol


Try this - http://jsfiddle.net/TpTsJ/ (the first two are the JSFiddle links - you won't have them on your page):

var links = document.getElementsByTagName("link");
for ( var i = 0; i < links.length; i++ ) {
    alert( links[i].getAttribute("rel") + ' : ' + links[i].getAttribute("href") );
}​
like image 41
Zoltan Toth Avatar answered Sep 29 '22 10:09

Zoltan Toth