get complete url using nginx and lua with openresty

Question

If request URL is

test.com/gifts.

If i am using

 ngx.var.uri

output is

/gifts/

expected output is

test.com/gifts

Code :

 location /gifts {
                    try_files $uri @url_change;
                }


                location @url_change {
                default_type text/html;
                content_by_lua '

                        ngx.say(ngx.var.uri)
                         ';
                }

Answer 1

I don't really understand what you want, but if you want the actual full URL i think you can use this

$http_host$request_uri;

Answer 2

If anyone is looking for the original request uri, it's here:

ngx.var.request_uri

While ngx.var.uri is the new uri after ngx rewrite phase.

Try it:

ngx.say(ngx.var.request_uri)

Answer 3

ngx.say(ngx.var.host .. '/' .. ngx.var.uri)

Answer 4

Isn't what you need just the $host variable, i.e. ngx.var.host?

Answer 5

Generate the full url and avoid getting an error when query_string is nil:

local full_url = ngx.var.scheme.."://"..ngx.var.http_host..ngx.var.request_uri
if ngx.var.query_string ~= nil then
  full_url = full_url.."?"..ngx.var.query_string
end
ngx.say(full_url)