Get all non-unique values (i.e.: duplicate/more than one occurrence) in an array

Question

I need to check a JavaScript array to see if there are any duplicate values. What's the easiest way to do this? I just need to find what the duplicated values are - I don't actually need their indexes or how many times they are duplicated.

I know I can loop through the array and check all the other values for a match, but it seems like there should be an easier way.

Similar question:

• Get all unique values in a JavaScript array (remove duplicates)

Answer 1

You could sort the array and then run through it and then see if the next (or previous) index is the same as the current. Assuming your sort algorithm is good, this should be less than O(n²):

const findDuplicates = (arr) => {    let sorted_arr = arr.slice().sort(); // You can define the comparing function here.     // JS by default uses a crappy string compare.    // (we use slice to clone the array so the    // original array won't be modified)    let results = [];    for (let i = 0; i < sorted_arr.length - 1; i++) {      if (sorted_arr[i + 1] == sorted_arr[i]) {        results.push(sorted_arr[i]);      }    }    return results;  }    let duplicatedArray = [9, 9, 111, 2, 3, 4, 4, 5, 7];  console.log(`The duplicates in ${duplicatedArray} are ${findDuplicates(duplicatedArray)}`);

In case, if you are to return as a function for duplicates. This is for similar type of case.

Reference: https://stackoverflow.com/a/57532964/8119511

Answer 2

If you want to elimate the duplicates, try this great solution:

function eliminateDuplicates(arr) {   var i,       len = arr.length,       out = [],       obj = {};    for (i = 0; i < len; i++) {     obj[arr[i]] = 0;   }   for (i in obj) {     out.push(i);   }   return out; }  console.log(eliminateDuplicates([1,6,7,3,6,8,1,3,4,5,1,7,2,6]))

Source: http://dreaminginjavascript.wordpress.com/2008/08/22/eliminating-duplicates/