Get all keys of a nested dictionary [duplicate]

Question

I have the below code which currently just prints the values of the initial dictionary. However I would like to iterate through every key of the nested dictionary to initially just print the names. Please see my code below:

Liverpool = {
    'Keepers':{'Loris Karius':1,'Simon Mignolet':2,'Alex Manninger':3},
    'Defenders':{'Nathaniel Clyne':3,'Dejan Lovren':4,'Joel Matip':5,'Alberto Moreno':6,'Ragnar Klavan':7,'Joe Gomez':8,'Mamadou Sakho':9}
}

for k,v in Liverpool.items():
    if k =='Defenders':
       print(v)

Answer 1

In other answers, you were pointed to how to solve your task for given dicts, with maximum depth level equaling to two. Here is the program that will alows you to loop through key-value pair of a dict with unlimited number of nesting levels (more generic approach):

def recursive_items(dictionary):
    for key, value in dictionary.items():
        if type(value) is dict:
            yield from recursive_items(value)
        else:
            yield (key, value)

a = {'a': {1: {1: 2, 3: 4}, 2: {5: 6}}}

for key, value in recursive_items(a):
    print(key, value)

Prints

1 2
3 4
5 6

---

That is relevant if you are interested only in key-value pair on deepest level (when value is not dict). If you are also interested in key-value pair where value is dict, make a small edit:

def recursive_items(dictionary):
    for key, value in dictionary.items():
        if type(value) is dict:
            yield (key, value)
            yield from recursive_items(value)
        else:
            yield (key, value)

a = {'a': {1: {1: 2, 3: 4}, 2: {5: 6}}}

for key, value in recursive_items(a):
    print(key, value)

Prints

a {1: {1: 2, 3: 4}, 2: {5: 6}}
1 {1: 2, 3: 4}
1 2
3 4
2 {5: 6}
5 6

Answer 2

Here is code that would print all team members:

for k, v in Liverpool.items():
    for k1, v1 in v.items():
        print(k1)

So you just iterate every inner dictionary one by one and print values.