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I can get the first index by doing:
l = [1,2,3,1,1]
l.index(1) = 0
How would I get a list of all the indexes?
l.indexes(1) = [0,3,4]
?
368
Method #1 : Using loop + set() In this, we just insert all the elements in set and then compare each element's existence in actual list. If it's the second occurrence or more, then index is added in result list.
duplicated() function Indicate duplicate index values. Duplicated values are indicated as True values in the resulting array. Either all duplicates, all except the first, or all except the last occurrence of duplicates can be indicated. The value or values in a set of duplicates to mark as missing.
>>> l = [1,2,3,1,1]
>>> [index for index, value in enumerate(l) if value == 1]
[0, 3, 4]
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