Get all dates between two dates in SQL Server

Question

My first suggestion would be use your calendar table, if you don't have one, then create one. They are very useful. Your query is then as simple as:

DECLARE @MinDate DATE = '20140101',
        @MaxDate DATE = '20140106';

SELECT  Date
FROM    dbo.Calendar
WHERE   Date >= @MinDate
AND     Date < @MaxDate;

If you don't want to, or can't create a calendar table you can still do this on the fly without a recursive CTE:

DECLARE @MinDate DATE = '20140101',
        @MaxDate DATE = '20140106';

SELECT  TOP (DATEDIFF(DAY, @MinDate, @MaxDate) + 1)
        Date = DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.object_id) - 1, @MinDate)
FROM    sys.all_objects a
        CROSS JOIN sys.all_objects b;

For further reading on this see:

• Generate a set or sequence without loops – part 1
• Generate a set or sequence without loops – part 2
• Generate a set or sequence without loops – part 3

With regard to then using this sequence of dates in a cursor, I would really recommend you find another way. There is usually a set based alternative that will perform much better.

So with your data:

  date   | it_cd | qty 
24-04-14 |  i-1  | 10 
26-04-14 |  i-1  | 20

To get the quantity on 28-04-2014 (which I gather is your requirement), you don't actually need any of the above, you can simply use:

SELECT  TOP 1 date, it_cd, qty 
FROM    T
WHERE   it_cd = 'i-1'
AND     Date <= '20140428'
ORDER BY Date DESC;

If you don't want it for a particular item:

SELECT  date, it_cd, qty 
FROM    (   SELECT  date, 
                    it_cd, 
                    qty, 
                    RowNumber = ROW_NUMBER() OVER(PARTITION BY ic_id 
                                                    ORDER BY date DESC)
            FROM    T
            WHERE   Date  <= '20140428'
        ) T
WHERE   RowNumber = 1;

You can use this script to find dates between two dates. Reference taken from this Article:

DECLARE @StartDateTime DATETIME
DECLARE @EndDateTime DATETIME

SET @StartDateTime = '2015-01-01'
SET @EndDateTime = '2015-01-12';

WITH DateRange(DateData) AS 
(
    SELECT @StartDateTime as Date
    UNION ALL
    SELECT DATEADD(d,1,DateData)
    FROM DateRange 
    WHERE DateData < @EndDateTime
)
SELECT DateData
FROM DateRange
OPTION (MAXRECURSION 0)
GO

Just saying...here is a more simple approach to this:

declare @sdate date = '2017-06-25'
    , @edate date = '2017-07-24';

with dates_CTE (date) as (
    select @sdate 
    Union ALL
    select DATEADD(day, 1, date)
    from dates_CTE
    where date < @edate
)
select *
from dates_CTE;

Easily create a Table Value Function that will return a table with all dates. Input dates as string You can customize the date in the the format you like '01/01/2017' or '01-01-2017' in string formats (103,126 ...)

Try this

CREATE FUNCTION [dbo].[DateRange_To_Table] ( @minDate_Str NVARCHAR(30), @maxDate_Str NVARCHAR(30))

RETURNS  @Result TABLE(DateString NVARCHAR(30) NOT NULL, DateNameString NVARCHAR(30) NOT NULL)

AS

begin

    DECLARE @minDate DATETIME, @maxDate DATETIME
    SET @minDate = CONVERT(Datetime, @minDate_Str,103)
    SET @maxDate = CONVERT(Datetime, @maxDate_Str,103)


    INSERT INTO @Result(DateString, DateNameString )
    SELECT CONVERT(NVARCHAR(10),@minDate,103), CONVERT(NVARCHAR(30),DATENAME(dw,@minDate))



    WHILE @maxDate > @minDate
    BEGIN
        SET @minDate = (SELECT DATEADD(dd,1,@minDate))
        INSERT INTO @Result(DateString, DateNameString )
        SELECT CONVERT(NVARCHAR(10),@minDate,103), CONVERT(NVARCHAR(30),DATENAME(dw,@minDate))
    END




    return

end   

To execute the function do this:

SELECT * FROM dbo.DateRange_To_Table ('01/01/2017','31/01/2017')

The output will be

01/01/2017  Sunday
02/01/2017  Monday
03/01/2017  Tuesday
04/01/2017  Wednesday
05/01/2017  Thursday
06/01/2017  Friday
07/01/2017  Saturday
08/01/2017  Sunday
09/01/2017  Monday
10/01/2017  Tuesday
11/01/2017  Wednesday
12/01/2017  Thursday
13/01/2017  Friday
14/01/2017  Saturday
15/01/2017  Sunday
16/01/2017  Monday
17/01/2017  Tuesday
18/01/2017  Wednesday
19/01/2017  Thursday
20/01/2017  Friday
21/01/2017  Saturday
22/01/2017  Sunday
23/01/2017  Monday
24/01/2017  Tuesday
25/01/2017  Wednesday
26/01/2017  Thursday
27/01/2017  Friday
28/01/2017  Saturday
29/01/2017  Sunday
30/01/2017  Monday
31/01/2017  Tuesday

This can be considered as bit tricky way as in my situation, I can't use a CTE table, so decided to join with sys.all_objects and then created row numbers and added that to start date till it reached the end date.

See the code below where I generated all dates in Jul 2018. Replace hard coded dates with your own variables (tested in SQL Server 2016):

select top (datediff(dd, '2018-06-30', '2018-07-31')) ROW_NUMBER() 
over(order by a.name) as SiNo, 
Dateadd(dd, ROW_NUMBER() over(order by a.name) , '2018-06-30') as Dt from sys.all_objects a

You can try this:

    SET LANGUAGE SPANISH

DECLARE @startDate DATE = GETDATE() -- Your start date
DECLARE @endDate DATE = DATEADD(MONTH, 16, GETDATE()) -- Your end date
DECLARE @years INT = YEAR(@endDate) - YEAR(@startDate)

CREATE TABLE #TMP_YEARS (
    [year] INT
)

-- Get all posible years between the start and end date
WHILE @years >= 0
BEGIN
    INSERT INTO #TMP_YEARS
    ([year])
    SELECT YEAR(@startDate) + @years

    SET @years = @years - 1
END

;WITH [days]([day]) AS -- Posible days at a month
(
    SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9 UNION ALL -- days lower than 10
    SELECT 10 UNION ALL SELECT 11 UNION ALL SELECT 12 UNION ALL SELECT 13 UNION ALL SELECT 14 UNION ALL SELECT 15 UNION ALL SELECT 16 UNION ALL SELECT 17 UNION ALL SELECT 18 UNION ALL SELECT 19 UNION ALL -- days lower than 20
    SELECT 20 UNION ALL SELECT 21 UNION ALL SELECT 22 UNION ALL SELECT 23 UNION ALL SELECT 24 UNION ALL SELECT 25 UNION ALL SELECT 26 UNION ALL SELECT 27 UNION ALL SELECT 28 UNION ALL SELECT 29 UNION ALL -- days lower than 30
    SELECT 30 UNION ALL SELECT 31 -- days higher 30
),
[months]([month]) AS -- All months at a year
(
    SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9 UNION ALL SELECT 10 UNION ALL SELECT 11 UNION ALL SELECT 12
)
SELECT CONVERT(VARCHAR, a.[year]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, n.[month]))) + CONVERT(VARCHAR, n.[month]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, d.[day]))) + CONVERT(VARCHAR, d.[day]) as [date]
  FROM #TMP_YEARS a
 CROSS JOIN [months] n -- Join all years with all months
 INNER JOIN [days] d on DAY(EOMONTH(CONVERT(VARCHAR, a.[year]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, n.[month]))) + CONVERT(VARCHAR, n.[month]) + '-' + CONVERT(VARCHAR, DAY(EOMONTH(CAST(CONVERT(VARCHAR, a.[year]) + '-' + CONVERT(varchar, n.[month]) + '-15' AS DATE)))))) >= d.[day] AND -- The number of the day can't be higher than the last day of the current month and the current year
                      CONVERT(VARCHAR, a.[year]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, n.[month]))) + CONVERT(VARCHAR, n.[month]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, d.[day]))) + CONVERT(VARCHAR, d.[day]) <= ISNULL(@endDate, GETDATE()) AND -- The current date can't be higher than the end date
                      CONVERT(VARCHAR, a.[year]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, n.[month]))) + CONVERT(VARCHAR, n.[month]) + '-' + REPLICATE('0', 2 - LEN(CONVERT(VARCHAR, d.[day]))) + CONVERT(VARCHAR, d.[day]) >= ISNULL(@startDate, GETDATE()) -- The current date should be higher than the start date
 ORDER BY a.[year] ASC, n.[month] ASC, d.[day] ASC

The output will be something like this, you can format the date as you like:

2019-01-24
2019-01-25
2019-01-26
2019-01-27
2019-01-28
2019-01-29
2019-01-30
2019-01-31
2019-02-01
2019-02-02
2019-02-03
2019-02-04
2019-02-05
2019-02-06
2019-02-07
2019-02-08
2019-02-09
...