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I have a list of items:
mylist = ['A','A','B','C','D','E','D']
I want to return a unique list of items that appear more than once in mylist, so that my desired output would be:
[A,D]
Not sure how to even being this, but my though process is to first append a count of each item, then remove anything equal to 1. Then dedupe, but this seems like a really roundabout, inefficient way to do it, so I am looking for advice.
753
Using Python's import numpy, the unique elements in the array are also obtained. In the first step convert the list to x=numpy. array(list) and then use numpy. unique(x) function to get the unique values from the list.
You can use the combination of the SUM and COUNTIF functions to count unique values in Excel. The syntax for this combined formula is = SUM(IF(1/COUNTIF(data, data)=1,1,0)). Here the COUNTIF formula counts the number of times each value in the range appears.
count() method to check if a value occurs multiple times in a list, e.g. if my_list. count(my_str) > 1: . The list. count() method will return an integer greater than 1 if the value occurs multiple times in the list.
One of the most basic ways to get the index positions of all occurrences of an element in a Python list is by using a for loop and the Python enumerate function. The enumerate function is used to iterate over an object and returns both the index and element.
You can use collections.Counter to do what you have described easily:
from collections import Counter
mylist = ['A','A','B','C','D','E','D']
cnt = Counter(mylist)
print [k for k, v in cnt.iteritems() if v > 1]
# ['A', 'D']
>>> mylist = ['A','A','B','C','D','E','D']
>>> set([i for i in mylist if mylist.count(i)>1])
set(['A', 'D'])
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