Get a Bright Random Colour Python

Question

Hi all, in my snake game program, I need to generate a random colour multiple times when the user selects a "Rainbow" theme. After looking online, I found this:

Generating a Random Hex Color in Python

The answer with the most votes gave a solution of

import random
r = lambda: random.randint(0,255)
print('#%02X%02X%02X' % (r(),r(),r()))

However, this program generates very dim colours as well; for example dark brown and sometimes even black. As you can see, some of those colours do not match a rainbow-y theme.

How would you change the above code so that you get vibrant colours like bright orange, pink, red, blue, etc, you get the idea. A hypothetical solution was to increase minimum value of randint r, but that just made all the colours very white. :'(

Plz, plz, plz, help will be very much appreciated.

Thanks guys!

Answer 1

Create a random HLS color (using numbers around .5 as the "level" parameter and numbers above .5 as the "saturation" parameter) and convert them to RGB:

import random
import colorsys
h,s,l = random.random(), 0.5 + random.random()/2.0, 0.4 + random.random()/5.0
r,g,b = [int(256*i) for i in colorsys.hls_to_rgb(h,l,s)]

That will ensure you'll always have highly saturated, bright colors.

Answer 2

If you start the random with a higher number the color will be lighter, for example:

import random

def random_color():
        rand = lambda: random.randint(100, 255)
        return '#%02X%02X%02X' % (rand(), rand(), rand())