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I have a need to duplicate slices (and part of the underlying array) so a caller won't mutate the original elements of an array. I think I can write a function to do this for arrays of specific types:
func duplicateSliceOfSomeType(sliceOfSomeType []SomeType) []SomeType {
dulicate := make([]SomeType, len(sliceOfSomeType))
copy(duplicate, sliceOfSomeType)
return duplicate
}
But is there a way to create the same method generically, perhaps without generics?
func duplicateSlice(slice []?) []?{
duplicate := make([]?, len(slice))
copy(duplicate, slice)
return duplicate
}
217
To duplicate a slice in Go, getting a deep copy of its contents, you need to either use the built-in copy() function, or create a new empty slice and add all the elements of the first slice to it using the append() function.
In Slice, you can copy one slice into another slice using the copy() function provided by the Go language. Or in other words, copy() function allows you to copy the elements of one slice into another slice.
In this article, we will see how to solve Copy An Array in rust code with examples. let arr =["a","b","c"]; // ES6 way const copy = [... arr]; // older method const copy = Array. from(arr);
To add an element to a slice , you can use Golang's built-in append method. append adds elements from the end of the slice. The first parameter to the append method is a slice of type T . Any additional parameters are taken as the values to add to the given slice .
You could write one simple statement to make a shallow copy of a slice,
b := append([]T(nil), a...)
Which is equivalent to,
b := make([]T, len(a))
copy(b, a)
For example,
package main
import "fmt"
type T int
func main() {
a := []T{4, 2}
b := append([]T(nil), a...)
fmt.Println(&a[0], a, &b[0], b)
b[0] = 9
fmt.Println(&a[0], a, &b[0], b)
}
Output:
0x10328000 [4 2] 0x10328020 [4 2]
0x10328000 [4 2] 0x10328020 [9 2]
ADDENDUM:
Common difficulties with reflection
If people are new to Go, they shouldn't be using reflection at all.
-rob
Reflection is subtle even for experts. It exposes details whose understanding depends on knowing pretty fundamental things about how the language works and, to a lesser extent, how it is implemented. It can be bewildering even for experienced Go programmers; for newly minted Gophers there are much more important, simpler things to learn first. Those who learn reflection too early confuse themselves cloud their understanding of those fundamentals. Best to keep it at arm's length until the rest of the picture is clear.
-rob
That said,
package main
import (
"fmt"
"reflect"
)
func CopySlice(s interface{}) interface{} {
t, v := reflect.TypeOf(s), reflect.ValueOf(s)
c := reflect.MakeSlice(t, v.Len(), v.Len())
reflect.Copy(c, v)
return c.Interface()
}
type T int
func main() {
{
// append
a := []T{4, 2}
b := append([]T(nil), a...)
fmt.Println(&a[0], a, &b[0], b)
b[0] = 9
fmt.Println(&a[0], a, &b[0], b)
}
{
// make and copy
a := []T{4, 2}
b := make([]T, len(a))
copy(b, a)
fmt.Println(&a[0], a, &b[0], b)
b[0] = 9
fmt.Println(&a[0], a, &b[0], b)
}
{
// reflection
a := []T{4, 2}
b := CopySlice(a).([]T)
fmt.Println(&a[0], a, &b[0], b)
b[0] = 9
fmt.Println(&a[0], a, &b[0], b)
}
}
Output:
0xc20800a200 [4 2] 0xc20800a210 [4 2]
0xc20800a200 [4 2] 0xc20800a210 [9 2]
0xc20800a290 [4 2] 0xc20800a2a0 [4 2]
0xc20800a290 [4 2] 0xc20800a2a0 [9 2]
0xc20800a310 [4 2] 0xc20800a320 [4 2]
0xc20800a310 [4 2] 0xc20800a320 [9 2]
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