Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

generic DAO in java

I am trying to develop generic DAO in java. I have tried the following. Is this a good way to implement generic DAO? I don't want to use hibernate. I am trying to make it as generic as possible so that I don't have to repeat the same code over and over again.

public abstract class  AbstractDAO<T> {

    protected ResultSet findbyId(String tablename, Integer id){
        ResultSet rs= null;
        try {
           // the following lines are not working
            pStmt = cn.prepareStatement("SELECT * FROM "+ tablename+ "WHERE id = ?");
            pStmt.setInt(1, id);
            rs = pStmt.executeQuery();


        } catch (SQLException ex) {
            System.out.println("ERROR in findbyid " +ex.getMessage() +ex.getCause());
            ex.printStackTrace();
        }finally{
            return rs;
        }

    }

}

Now I have:

public class UserDAO extends AbstractDAO<User>{

  public List<User> findbyid(int id){
   Resultset rs =findbyid("USERS",id) // "USERS" is table name in DB
   List<Users> users = convertToList(rs);
   return users; 
}


 private List<User> convertToList(ResultSet rs)  {
        List<User> userList= new ArrayList();
        User user= new User();;
        try {
            while (rs.next()) {
                user.setId(rs.getInt("id"));
                user.setUsername(rs.getString("username"));
                user.setFname(rs.getString("fname"));
                user.setLname(rs.getString("lname"));
                user.setUsertype(rs.getInt("usertype"));
                user.setPasswd(rs.getString("passwd"));
                userList.add(user);
            }
        } catch (SQLException ex) {
            Logger.getLogger(UserDAO.class.getName()).log(Level.SEVERE, null, ex);
        }

        return userList;

    }
}
like image 929
akshay Avatar asked May 17 '10 11:05

akshay


People also ask

What is generic DAO in Java?

Simple generic DAO structure for Java. Note that the interface takes two generic parameters, one for the primary key type, and the second for the bean type, which uses the same primary key. This enables you to use any kind of object as a primary key, making your code very flexible.

What is DAO in Java example?

The Data Access Object (DAO) pattern is a structural pattern that allows us to isolate the application/business layer from the persistence layer (usually a relational database but could be any other persistence mechanism) using an abstract API.

What is DAO and DTO in Java?

DTO — Data Transfer Object. DAO — Data Access Object.

Is JPARepository a DAO?

It is about the DAO. In spring boot, there is JPARepository interface. This interface has been declare the methods such as save(), findById() . and we can use the JPARepository as follows.


3 Answers

My advice:

  • Don't write a generic DAO; Generic classes come back to bite you when you realise they don't quite do what you need in a specific situation and often end up growing in complexity to cover the ever-increasing array of use-cases. Better to code application specific DAOs and then attempt to generify any common behaviour later on.
  • Consider using Spring JDBC to write app-specific DAOs but in a much more compact and less error-prone fashion than JDBC. Also, unlike Hibernate, Spring JDBC only acts a thin wrapper around raw JDBC giving you finer grained control and more visibility.

Example

// Create or inject underlying DataSource.
DataSource ds = ...
// Initialise Spring template, which we'll use for querying.
SimpleJdbcTemplate tmpl = new SimpleJdbcTemplate(ds);     

// Create collection of "Role"s: The business object we're interested in.
Set<Role> roles = new HashSet<Role>();

// Query database for roles, use row mapper to extract and create
// business objects and add to collection.  If an error occurs Spring
// will translate the checked SQLException into an unchecked Spring
// DataAccessException and also close any open resources (ResultSet, Connection).
roles.addAll(tmpl.query("select * from Role", new ParameterizedRowMapper<Role>() {
  public Role mapRow(ResultSet resultSet, int i) throws SQLException {
    return new Role(resultSet.getString("RoleName"));
  }
}));
like image 191
Adamski Avatar answered Sep 27 '22 22:09

Adamski


If you can live with Spring, I will suggest the following improvements:

  • Let Spring do the exception handling.
  • Use JdbcTemplate instead of creating prepared statements yourself.

Independent of using Spring, I will recommend the following:

  • Don't send the table name as parameter. That should be done in the initialization phase.
  • Use a String on the id parameter, since that's much more generic.
  • Consider returning a generic object instead of a collection, since the collection should always contain only one object.

An improved AbstractDao with Spring:

import java.util.Collection;

import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.jdbc.core.RowMapper;

public abstract class AbstractDao<T> {

    protected final RowMapper<T> rowMapper;

    protected final String findByIdSql;

    protected final JdbcTemplate jdbcTemplate;

    protected AbstractDao(RowMapper<T> rowMapper, String tableName,
            JdbcTemplate jdbcTemplate) {
        this.rowMapper = rowMapper;
        this.findByIdSql = "SELECT * FROM " + tableName + "WHERE id = ?";
        this.jdbcTemplate = jdbcTemplate;
    }

    public  Collection<T> findById(final String id) {
        Object[] params = {id};
        return jdbcTemplate.query(findByIdSql, params, rowMapper);
    }
}

As you see, no exception handling or hacking with the primitive SQL classes. This templates closes the ResultSet for you, which I can't see in your code.

And the UserDao:

import java.sql.ResultSet;
import java.sql.SQLException;

import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.jdbc.core.RowMapper;

public class UserDao extends AbstractDao<User> {

    private final static String TABLE_NAME = "USERS";

    public UserDao(JdbcTemplate jdbcTemplate) {
        super(new UserRowMapper(), TABLE_NAME, jdbcTemplate);
    }

    private static class UserRowMapper implements RowMapper<User> {
        public User mapRow(ResultSet rs, int rowNum) throws SQLException {
            User user = new User();
            user.setUserName(rs.getString("username"));
            user.setFirstName(rs.getString("fname"));
            user.setLastName(rs.getString("lname"));

            return user;
        }
    }
}

Updated:

When you know the id and the id corresponds to a single row in the database, you should consider returning a generic object instead of a collection.

public T findUniqueObjectById(final String id) {
    Object[] params = {id};
    return jdbcTemplate.queryForObject(findByIdSql, params, rowMapper);
}

This makes your service code more readable, since you don't need to retrieve the user from a list, but only:

User user = userDao.findUniqueObjectById("22");
like image 35
Espen Avatar answered Sep 27 '22 21:09

Espen


It is okay but change the method

private List<User> convertToList(ResultSet rs)  { 
        List<User> userList= new ArrayList(); 
        User user= new User();; 
        try { 
            while (rs.next()) { 
                user.setId(rs.getInt("id")); 
                user.setUsername(rs.getString("username")); 
                user.setFname(rs.getString("fname")); 
                user.setLname(rs.getString("lname")); 
                user.setUsertype(rs.getInt("usertype")); 
                user.setPasswd(rs.getString("passwd")); 
                userList.add(user); 
            } 
        } catch (SQLException ex) { 
            Logger.getLogger(UserDAO.class.getName()).log(Level.SEVERE, null, ex); 
        } 

        return userList; 

    } 

to

private List<User> convertToList(ResultSet rs)  { 
        List<User> userList= new ArrayList<User>(); 
        try { 
            while (rs.next()) { 
                User user= new User();
                user.setId(rs.getInt("id")); 
                user.setUsername(rs.getString("username")); 
                user.setFname(rs.getString("fname")); 
                user.setLname(rs.getString("lname")); 
                user.setUsertype(rs.getInt("usertype")); 
                user.setPasswd(rs.getString("passwd")); 
                userList.add(user); 
            } 
        } catch (SQLException ex) { 
            Logger.getLogger(UserDAO.class.getName()).log(Level.SEVERE, null, ex); 
        } 

        return userList; 

    } 

User object should be created inside while loop.

like image 45
Ravindra Gullapalli Avatar answered Sep 27 '22 23:09

Ravindra Gullapalli