Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

generate random 64 bit integer

Tags:

c++

random

64-bit

I need your help and please give me some advice. From programming pearls I know that to generate random 30 bit integer we should write it like this:

RAND_MAX*rand()+rand()

But what could I do for generating not 30, but 64 bit random integer instead? I think that is very inefficient method if I multiply two 30 bit integers and then multiply again 4 bit integer, so what kind of method should I use? I am using now popcount_1 different method for 64 bit one and I would like to test it on random integers(I am also measuring the time which each one takes to accomplish the task)

like image 582
dato datuashvili Avatar asked Nov 14 '11 10:11

dato datuashvili


3 Answers

First, I have my doubts about the solution you post for a 30 bit integer. RAND_MAX itself could be a 31 bit value, and RAND_MAX * rand() + rand() is likely to overflow, producing undefined behavior (and in practice, negative values).

If you need a value larger than the guaranteed minimum of RAND_MAX, or for that matter, anything that isn't significantly smaller than RAND_MAX, the only solution will be to use successive calls to rand(), and combine the values, but you need to do this carefully, and validate the results. (Most implementations of rand() use linear congruent generators, which while adequate for some tasks, aren't particularly good in this case.) Anyway, something like:

unsigned 
rand256()
{
    static unsigned const limit = RAND_MAX - RAND_MAX % 256;
    unsigned result = rand();
    while ( result >= limit ) {
        result = rand();
    }
    return result % 256;
}

unsigned long long
rand64bits()
{
    unsigned long long results = 0ULL;
    for ( int count = 8; count > 0; -- count ) {
        results = 256U * results + rand256();
    }
    return results;
}

(The code in rand256 is designed to eliminate the otherwise unavoidable bias you get when mapping RAND_MAX values to 256 values.)

like image 142
James Kanze Avatar answered Sep 18 '22 01:09

James Kanze


This could be a solution, without multiplication:

r30 = RAND_MAX*rand()+rand()
s30 = RAND_MAX*rand()+rand()
t4  = rand() & 0xf

res = (r30 << 34) + (s30 << 4) + t4
like image 43
duedl0r Avatar answered Sep 21 '22 01:09

duedl0r


If boost is an option, you could use boost random.

like image 28
Andrea Bergia Avatar answered Sep 19 '22 01:09

Andrea Bergia