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I need to generate a list of numbers in a specific format. The format is
mylist = [00,01,02,03,04,05,06,07,08,09,10,11,12,13,14,15] #Numbers between 0-9 are preceded by a zero. I know how to generate a normal list of numbers using range
>>> for i in range(0,16): ... print i So, is there any built-in way in python to generate a list of numbers in the specified format.
815
To start a numbered list, type 1, a period (.), a space, and some text. Word will automatically start a numbered list for you. Type* and a space before your text, and Word will make a bulleted list. To complete your list, press Enter until the bullets or numbering switch off.
To create a list of numbers from 1 to N: Use the range() class to create a range object from 1 to N. Use the list() class to convert the range object to a list. The new list will contain the numbers in the specified range.
Python string formatting allows you to specify a precision:
Precision (optional), given as a '.' (dot) followed by the precision.
In this case, you can use it with a value of 2 to get what you want:
>>> ["%.2d" % i for i in range(16)] ['00', '01', '02', '03', '04', '05', '06', '07', '08', '09', '10', '11', '12', '13', '14', '15'] You could also use the zfill function:
>>> str(3).zfill(2) '03' or the string format function:
>>> "{0:02d}".format(3) '03' If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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