GDB remote debugging, can't seem to find symbols

Question

I'm trying to remote debug an application running on a machine with address 192.168.98.64. On that machine I run:

gdbserver serveripaddr:4444 progname

then from the server I run "gdb", then at the gdb prompt run:

(gdb)  target remote 192.168.98.64:4444
Remote debugging using 192.168.98.64:4444
[New Thread 28432]
warning: Could not load vsyscall page because no executable was specified
try using the "file" command first.
0xb775e810 in ?? ()
(gdb) break internal[TAB]

I was expecting a press of the TAB key when trying to set my breakpoint to bring up a list of corresponding functions starting with internal, but it doesn't bring up anything. The code has been compiled with debugging turned on with -g. What am I doing wrong?

Answer 1

I run "gdb"

You are supposed to give GDB the executable you are debugging (preferably a non-stripped version of it):

gdb /path/to/progname
(gdb) target remote 192.168.98.64:4444

Answer 2

I just encountered this problem myself when I used a cross-compiled gdb (you will in general need this if your remote host has a different architecture). In this case the symbols need to be read from the binary compiled on the remote host. I figured out that the following works for me (also if the architectures on the hosts are the same):

On the remote host:

gdbserver [host]:[port] [remote-path-to-binary-from-gdbserver-workdir]

and then on the local host in (cross-compiled) gdb:

shell sleep 5
target remote [host]:[port]
symbol-file remote:[remote-path-to-binary-from-gdbserver-workdir]
directory [local-root-directory-for-source-files]
continue

Replace the [*] with your data. You can use it as a gdb script (hence the sleep in the first line) or enter it on your gdb command line. The optional directory line tells it to add the local source directory to the search path for sources. This can be useful if you use a frontend which points you to the source code.