I'm running below code to clean text
import pandas as pd
def not_regex(pattern):
return r"((?!{}).)".format(pattern)
tmp = pd.DataFrame(['No one has a European accent either @',
'That the kid reminds me of Kevin'])
tmp[0].str.replace(not_regex('(\\b[-/]\\b|[a-zA-Z0-9])'), ' ')
Then it returns a warning
<ipython-input-8-ef8a43f91dbd>:9: FutureWarning: The default value of regex will change from True to False in a future version.
tmp[0].str.replace(not_regex('(\\b[-/]\\b|[a-zA-Z0-9])'), ' ')
Could you please elaborate on the reason of this warning?
The \r metacharacter matches carriage return characters.
In the case of regular expressions, a regex pattern has to be passed. This pattern represents a generic sequence of characters. regex : For pandas to interpret the replacement as regular expression replacement, set it to True. value : This represents the value to be replaced in place of to_replace values.
A Regular Expression is used for identifying a search pattern in a text string. It also helps in finding out the correctness of the data and even operations such as finding, replacing and formatting the data is possible using Regular Expressions.
Regex can be used to perform various tasks in Python. It is used to do a search and replace operations, replace patterns in text, check if a string contains the specific pattern.
Warning: FutureWarning: The default value of regex will change from True to False in a future version. FutureWarning: The default value of regex will change from True to False in a future version. It means that you will need to explicitly set the regex parameter for replace method:
accUtils.py FutureWarning: The default value of regex will change from True to False in a future version. · Issue #178 · OxWearables/biobankAccelerometerAnalysis · GitHub
In addition, single character regular expressions will not be treated as literal strings when regex=True is set ( GH24804) Show activity on this post. Thanks for contributing an answer to Stack Overflow! Please be sure to answer the question. Provide details and share your research! But avoid …
FutureWarning: Default solver will be changed to 'lbfgs' in 0.22. Specify a solver to silence this warning. This issue involves a change from the ‘ solver ‘ argument that used to default to ‘ liblinear ‘ and will change to default to ‘ lbfgs ‘ in a future version.
See Pandas 1.2.0 release notes:
The default value of regex for
Series.str.replace()
will change from True to False in a future release. In addition, single character regular expressions will not be treated as literal strings when regex=True is set (GH24804)
I.e., use regular expressions explicitly now:
dframe['colname'] = dframe['colname'].str.replace(r'\D+', regex=True)
I have like
df.Experience.head(5)
0 24 years experience
1 12 years experience
2 9 years experience
3 12 years experience
4 20 years experience
Name: Experience, dtype: object
I use like
df['Experience']=df['Experience'].str.replace(r'\D+','', regex=True).astype(int)
I get like
df.Experience.head(5)
0 24
1 12
2 9
3 12
4 20
Name: Experience, dtype: int64
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With