Function returns promise object instead of value (async/await) [duplicate]

Question

I got this code using the async/await :

function _getSSID(){
   return new Promise((resolve, reject)=>{
      NetworkInfo.getSSID(ssid => resolve(ssid))
   })
}

async function getSSID(){
   let mySSID =  await _getSSID()
   if (mySSID == "error") {
     return 'The value I want to return'
   }
}

And getSSID() is equal to this :

Looks like the getSSID() function will always return a promise. How can I get "The value I want to return" in plain text ?

Any help is greatly appreciated.

Answer 1

Declaring a function async means that it will return the Promise. To turn the Promise into a value, you have two options.

The "normal" option is to use then() on it:

getSSID().then(value => console.log(value));

You can also use await on the function:

const value = await getSSID();

The catch with using await is it too must be inside of an async function.

At some point, you'll have something at the top level, which can either use the first option, or can be a self-calling function like this:

((async () => {
    const value = await getSSID();
    console.log(value);
})()).catch(console.error):

If you go with that, be sure to have a catch() on that function to catch any otherwise uncaught exceptions.

You can't use await at the top-level.