Function overloading

Question

I found this code , and i m not sure that whether overloading should happen or not.

void print( int (*arr)[6], int size );

void print( int (*arr)[5], int size );

what happens if I pass pointer to an array of 4 elements , to it should come...

any thread will be helpful.

Answer 1

Overloading will happen, and passing the pointer to the array of 4 int's will not match either function. It's clearer if you write them as the equivalent form:

void print( int arr[][6], int size );
void print( int arr[][5], int size );

An N×4 array can be decayed to a pointer to array of 4 int's. And it's well known that 2D arrays having different 2nd dimensions are incompatible.