Function not returning random integer for variable

Question

I have a very simple problem, when I run the following code:

from random import randint

def create_random():
  x = random.randint(1,4)
  return x 

print(create_random)

The output comes to this:

< function create_random at 0x7f5994bd4f28 >

Note: every character between "0x7f" and "f28" are random each time the code is run.

My goal was to be able to call the function multiple times with x being assigned a new integer value between 1 and 3 with each invocation.

Answer 1

You aren't actually calling the function. To do this you need to do:

print(create_random())

Just now you're printing the reference to the function which isn't very helpful for you in this case.