I understand how to go from a vector to a raw pointer but im skipping a beat on how to go backwards.
// our host vector
thrust::host_vector<dbl2> hVec;
// pretend we put data in it here
// get a device_vector
thrust::device_vector<dbl2> dVec = hVec;
// get the device ptr
thrust::device_ptr devPtr = &d_vec[0];
// now how do i get back to device_vector?
thrust::device_vector<dbl2> dVec2 = devPtr; // gives error
thrust::device_vector<dbl2> dVec2(devPtr); // gives error
Can someone explain/point me to an example?
http://code.google.com/p/thrust/source/browse/examples/cuda/wrap_pointer.cu
Thrust provides a good example for this question.
#include <thrust/device_ptr.h>
#include <thrust/fill.h>
#include <cuda.h>
int main(void)
{
size_t N = 10;
// obtain raw pointer to device memory
int * raw_ptr;
cudaMalloc((void **) &raw_ptr, N * sizeof(int));
// wrap raw pointer with a device_ptr
thrust::device_ptr<int> dev_ptr = thrust::device_pointer_cast(raw_ptr);
// use device_ptr in Thrust algorithms
thrust::fill(dev_ptr, dev_ptr + N, (int) 0);
// access device memory transparently through device_ptr
dev_ptr[0] = 1;
// free memory
cudaFree(raw_ptr);
return 0;
}
And getting the raw pointer from thrust containers is as answered already by yourself..
dbl2* ptrDVec = thrust::raw_pointer_cast(&d_vec[0]);
You initialize and populate thrust vectors just like standard containers, i.e. via iterators:
#include <thrust/device_vector.h>
#include <thrust/device_ptr.h>
int main()
{
thrust::device_vector<double> v1(10); // create a vector of size 10
thrust::device_ptr<double> dp = v1.data(); // or &v1[0]
thrust::device_vector<double> v2(v1); // from copy
thrust::device_vector<double> v3(dp, dp + 10); // from iterator range
thrust::device_vector<double> v4(v1.begin(), v1.end()); // from iterator range
}
In your simple example there's no need to go the detour via pointers, as you can just copy the other container directly. In general, if you have a pointer to the beginning of an array, you can use the version for v3
if you supply the array size.
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