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What is the best way to release memory allocated by an array of bytes (new byte[size] in Java)?
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yourArray = null; In Java garbage collection is automatic. If the JVM can detect that a piece of memory is no longer reachable by the entire program, then the JVM will free the memory for you. The JVM will free the memory when it feels like it.
Byte Data Type A Java byte is the same size as a byte in computer memory: it's 8 bits, and can hold values ranging from -128 to 127.
Java uses managed memory, so the only way you can allocate memory is by using the new operator, and the only way you can deallocate memory is by relying on the garbage collector.
According to the 64-bit memory model, an int is 4 bytes, so all the elements will be 4*N bytes in size. In addition to that, Java has a 24 bytes array overhead and there's also 8 bytes for the actual array object. So that's a total of 32 + 4 * N bytes. For a 2 dimensional array: int a[][] = new int[N][M];
Stop referencing it.
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When creating a new byte[] in Java, you do something like
byte[] myArray = new byte[54]; To free it, you should do
myArray = null; If something else references your byte array, like
yourArray = myArray; you need to also set the other references to null, like so
yourArray = null; In Java garbage collection is automatic. If the JVM can detect that a piece of memory is no longer reachable by the entire program, then the JVM will free the memory for you.
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