Format specifier %02x

Question

I have a simple program :

#include <stdio.h> int main() {         long i = 16843009;         printf ("%02x \n" ,i); } 

I am using %02x format specifier to get 2 char output, However, the output I am getting is:

1010101  

while I am expecting it to be :01010101 .

Answer 1

%02x means print at least 2 digits, prepend it with 0's if there's less. In your case it's 7 digits, so you get no extra 0 in front.

Also, %x is for int, but you have a long. Try %08lx instead.

Answer 2

%x is a format specifier that format and output the hex value. If you are providing int or long value, it will convert it to hex value.

%02x means if your provided value is less than two digits then 0 will be prepended.

You provided value 16843009 and it has been converted to 1010101 which a hex value.