format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘int *’

Question

Each time I submit a program on hackerrank the following error occurs.

solution.c: In function ‘main’:
solution.c:22:14: warning: format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘int *’ [-Wformat=]
 printf("%d", &sum);

It would be very helpful if someone could tell me what this means?

Answer 1

I assume that you have declared sum as an int. So the correct call to printf is :

printf("%d", sum);

as %d specifier means that you are going to print an int, but you are passing the int's address, which is a pointer to int, or int *.

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NOTE : Do not confuse printf with scanf, as the second does require a pointer. So, for reading variable sum, you would use :

scanf("%d", &sum);

but for printing, the correct way is without &, as written above.