Possible Duplicate:
The following bash command will spawn processes to kernel death. Can you explain the syntax?
:(){ :|:& };:
running this fork() unlimited .. Can one please explain this bash script ?
You define a function called :
. Inside this function you call this function twice (:|:
) and then you send that process to the background (&
). Then you finally call it at the end.
Because of the recursive nature, you'll keep forking. Since there is no base case, the recursion will never end.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With