I'm quite new to hibernate and have stumbled on this problem, which I can't find solution for.
When persisting parent object (with one-to-many relationship with child), the foreign-key to this parent is not stored in child's table.
My classes:
@javax.persistence.Table(name = "PARENT")
@Entity
public class PARENT {
private Integer id;
@javax.persistence.Column(name = "ID")
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
private Collection<Child> children;
@OneToMany(mappedBy = "parent", fetch = FetchType.EAGER, cascade = {CascadeType.ALL})
@Cascade({org.hibernate.annotations.CascadeType.ALL})
public Collection<Child> getChildren() {
return children;
}
public void setChildren(Collection<Child> children) {
this.children = children;
}
}
@javax.persistence.Table(name = "CHILD")
@Entity
@IdClass(Child.ChildId.class)
public class Child {
private String childId1;
@Id
public String getChildId1() {
return childId1;
}
public void setChildId1(String childId1) {
this.childId1 = childId1;
}
private String childId2;
@Id
public String getChildId2() {
return childId2;
}
public void setChildId2(String childId2) {
this.childId2 = childId2;
}
private Parent parent;
@ManyToOne
@javax.persistence.JoinColumn(name = "PARENT_ID", referencedColumnName = "ID")
public Parent getParent() {
return parent;
}
public void setParent(Operation parent) {
this.parent = parent;
}
public static class ChildId implements Serializable {
private String childId1;
@javax.persistence.Column(name = "CHILD_ID1")
public String getChildId1() {
return childId1;
}
public void setChildId1(String childId1) {
this.childId1 = childId1;
}
private String childId2;
@javax.persistence.Column(name = "CHIILD_ID2")
public String getChildId2() {
return childId2;
}
public void setChildId2(String childId2) {
this.childId2 = childId2;
}
public ChildId() {
}
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
ChildId that = (ChildId) o;
if (childId1 != null ? !childId1.equals(that.childId1) : that.childId1 != null)
return false;
if (childId2 != null ? !childId2.equals(that.childId2) : that.childId2 != null)
return false;
return true;
}
@Override
public int hashCode() {
int result = childId1 != null ? childId1.hashCode() : 0;
result = 31 * result + (childId2 != null ? childId2.hashCode() : 0);
return result;
}
}
}
public class Test() {
private ParentDao parentDao;
public void setParentDao(ParentDao parentDao) {
this.parentDao = parentDao;
}
private ChildDao childDao;
public void setChildDao(ChildDao childDao) {
this.childDao = parentDao;
}
test1() {
Parent parent = new Parent();
Child child = new Child();
child.setChildId1("a");
child.setChildId2("b");
ArrayList<Child> children = new ArrayList<Child>();
children.add(child);
parent.setChildren(children);
parent.setValue("value");
parentDao.save(parent); //calls hibernate's currentSession.saveOrUpdate(entity)
}
test2() {
Parent parent = new Parent();
parent.setValue("value");
parentDao.save(parent); //calls hibernate's currentSession.saveOrUpdate(entity)
Child child = new Child();
child.setChildId1("a");
child.setChildId2("b");
child.setParent(parent);
childDao.save(); //calls hibernate's currentSession.saveOrUpdate(entity)
}
}
When calling test1(), both entities get written to database, but field PARENT_ID in CHILD table stays empty.
The only workaround I have so far is test2() - persisting parent first, and then the child.
My goal is to persist parent and its children in one call to save() on Parent. Any ideas?
You can also add an extra method to your parent like
public void addChild(Child child)
which does something like
child.setParent(this);
I have a good solution for that case:D
mappedBy means inverse = "true" . so you must inverse = "false"
try it..
@OneToMany(fetch = FetchType.EAGER, cascade ={CascadeType.ALL})//javax.persistent.CascadeType
@JoinColumn(name = "parent_id")//parent's foreign key
public Collection<Child> getChildren() {
return children;
}
I hope it s good to be work
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