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Is there anyway to force a constraints for a generic definition to implement a "generic interface" ... that is, I want the class to support passing an interface and a generic class constraining it so that the class implements the interface. For example if I say:
MyGenericClass<IMyInterface, MyImplementation>.DoSomething();
That should be constrained so that MyImplementation implements IMyInterface
As far as I know that can be achieved by
public class Dynamic_Loader<T, S> where S: T
Now, is there anyway to also force T to be an interface?
Edit: The purpose of this was to have something like:
private static List<T> interfaceList = new List<T>();
public static List<T> InterfaceList {get { return interfaceList;}}
public static void Add(S input) { interfaceList.Add(input);}
and have the list restricted to only interfaces (since it is supposed to return implementations of certain interfaces)
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Only generic classes can implement generic interfaces. Normal classes can't implement generic interfaces.
With using generics, your code will become reusable, type safe (and strongly-typed) and will have a better performance at run-time since, when used properly, there will be zero cost for type casting or boxing/unboxing which in result will not introduce type conversion errors at runtime.
Constraints can specify interfaces, base classes, or require a generic type to be a reference, value, or unmanaged type. They declare capabilities that the type argument must have, and must be placed after any declared base class or implemented interfaces.
The general syntax to declare a generic interface is as follows: interface interface-name<T> { void method-name(T t); // public abstract method. } In the above syntax, <T> is called a generic type parameter that specifies any data type used in the interface.
Do you mean, can a constraint also be put on T like where T : interface?
If so, then no: this list pretty much covers your options.
What you have is as close as it gets, I believe.
Out of curiosity, what would be your reason for wanting to constrain T to be an interface?
Or do you mean can a constraint also be put on T for T to implement some specific interface?
If so, then yes: simply have two where clauses (e.g., where S : T where T : U).
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