Flutter Open AppStore/PlayStore URL

Question

How can I open a specific URL of the PlayStore/AppStore with flutter on Android and IOS, depending on which smartphone it is executed? I mean I want to open the application and not a browser or something like this.

In this thread I found some native way for android but how can I do this with flutter?

final String appPackageName = getPackageName(); // getPackageName() from Context or Activity object try {     startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("market://details?id=" + appPackageName))); } catch (android.content.ActivityNotFoundException anfe) {     startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://play.google.com/store/apps/details?id=" + appPackageName))); } 

If there is currently no way to do this, it would be a nice feature to implement for the plugin url_launcher.

Answer 1

You can use this Library,

Basically, To use this plugin, add launch_review as a dependency in your pubspec.yaml file.

launch_review: ^1.0.1 

To use :

 import 'package:launch_review/launch_review.dart';  

Then invoke the static launch method of LaunchReview anywhere in your Dart code. If no arguments are provided, it will consider the current package.

LaunchReview.launch(); 

To open the App Store page for any other applications, you can pass the app Id.

LaunchReview.launch(androidAppId: <package name>,                 iOSAppId: <ios app id>); 

Answer 2

You can do something similar in flutter:

import 'package:url_launcher/url_launcher.dart';  try {   launch("market://details?id=" + appPackageName); } on PlatformException catch(e) {     launch("https://play.google.com/store/apps/details?id=" + appPackageName);         } finally {   launch("https://play.google.com/store/apps/details?id=" + appPackageName);         } 

The exception/catch does not seem to work for some reason so adding 'finally' did the trick, finally :)